If #f(x) =sin(-x/4) # and #g(x) = sqrt(x^3+3 #, what is #f'(g(x)) #? Calculus Basic Differentiation Rules Chain Rule 1 Answer kubik98 Dec 9, 2017 Below Explanation: #f(x)=sin(−x/4)# #g(x)=sqrt(x^3+3)# #f(g(x))=sin(−sqrt(x^3+3)/4)# #f^'(g(x))=cos(−sqrt(x^3+3)/4)*-1/4*1/(2sqrt(x^3+3))*3x^2# #f^'(g(x))=cos(−sqrt(x^3+3)/4)*(-3x^2)/(8sqrt(x^3+3))# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1564 views around the world You can reuse this answer Creative Commons License