If #f(x)= sin(- x -1) # and #g(x) = 4x^2 -5 #, how do you differentiate #f(g(x)) # using the chain rule? Calculus Basic Differentiation Rules Chain Rule 1 Answer Trevor Ryan. Mar 23, 2016 #d/dx(f[g(x)])=-8xcos(5-4x^2)# Explanation: #f[g(x)]=f(4x^2-5)# #=sin[-(4x^2-5)]# #=sin(5-4x^2)# #therefore d/dx[sin(5-4x^2)]=-8xcos(5-4x^2)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1366 views around the world You can reuse this answer Creative Commons License