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If #f(x) =-e^(-3x-7) # and #g(x) = -2sec^2x #, what is #f'(g(x)) #?

1 Answer

A. S. Adikesavan

Feb 15, 2017

#=12e^(-7)e^(6sec^2x)sec^2xtanx#.

Explanation:

#f(g)=-e^(-3g-7)=e^(-7)e^(6sec^2x)#

So, #f'(g)=(df)/(dx)#

#=e^(-7)e(6sec^2x)(6sec^2x)'#

#=e^(-7)e(6sec^2x)12secx(secx)'#

#=12e^(-7)e^(6sec^2x)sec^2xtanx#.

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