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If #f(x) =-e^(-2x-7) # and #g(x) = 3/x #, what is #f'(g(x)) #?

1 Answer

Nov 19, 2017

#f'(g(x))=2e^(-6/x-7)#

Explanation:

First thing is to calculate the derivate of #f(x)#,
#f'(x)=2e^(-2x-7)#

and now we substitute #g(x)# in every #x# of the #f'(x)#,
#f'(g(x))=2e^(-2·3/x-7)=2e^(-6/x-7)#

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