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If #f(x) =-e^(2x-1) # and #g(x) = 5sin^2x^2 #, what is #f'(g(x)) #?

1 Answer

Shwetank Mauria

May 12, 2016

#f'(g(x))=-2e^(10sin^2x^2-1)#

Explanation:

#f(x)=-e^(2x-1)# and #g(x)=5sin^2x^2#

Therefore, #f'(x)=-e^(2x-1)xxd/dx(2x-1)=-2e^(2x-1)#

Hence, #f'(g(x))=-2e^(2xx5sin^2x^2-1)#

or #f'(g(x))=-2e^(10sin^2x^2-1)#

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