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If #f(x) =cos3x # and #g(x) = (2x-1)^2 #, what is #f'(g(x)) #?

1 Answer

Shwetank Mauria

Mar 21, 2016

#(df)/(dg)=(-3sin3x)/(4(2x-1))#

Explanation:

As per chain formula #(df)/(dx)=(df)/(dg)xx(dg)/(dx)#. hence

#(df)/(dg)=((df)/(dx))/((dg)/(dx))#

As #f(x)=sin3x# and #g(x)=(2x-1)^2#

#(df)/(dx)=-sin3x xx3# and #(dg)/(dx)=2(2x-1)xx2#

Hence #(df)/(dg)=(-3sin3x)/(4(2x-1))#

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