Hydrogen sulfide reacts with sulfur dioxide to give H2O and S, H2S + SO2 = H2O + S(solid), unbalanced. If 6.0 L of H2S gas at 750 torr produced 3.2 g of sulfur, what is the temperature in Celsius?

Question

14960 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2014-08-09T18:58:35

The temperature is 810 °C.

There are four steps in this problem:

1. Write the balanced chemical equation

2H₂S + SO₂ → 2H₂O + 3S

2. Calculate the moles of sulfur

Moles of S = 3.2 g S × #(1"mol S")/(32.06"g S")# = 0.0998 mol S

3. Calculate the moles of H₂S

Moles of H₂S = 0.0998 mol S × #(2"mol H₂S")/(3"mol S")# = 0.0665 mol H₂S

4. Calculate the temperature

#P# = 750 Torr × #(1"atm")/(760"Torr")# = 0.9868 atm

#PV = nRT#

#T = (PV)/(nR) = (0.9868"atm" × 6.0"L")/(0.0665"mol" × 0.082 06"L·atm·K⁻¹mol⁻¹")# = 1080 K

#T# = (1080 – 273.15) °C = 810 °C (2 significant figures)