HT bisects DG at O. If HO=3x+17, TO=4x-2, DO= 3x+10 and GO= 6x-20, how do you find the value of x?

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Answer 1 · 2017-07-20T18:32:06

#x=10#

#HT# is the perpendicular bisector of #DG# which means that
#DO = OG#

#DG# is not automatically the bisector of #HT#, so you do NOT know that #HO= OT#

Find #x# if #OG = DO#

#6x-20 = 3x+10#

#6x-3x=10+20#

#3x =30#

#x =10#