How to write an equation in standard form for a line through (1,-5); slope -3/2?

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Answer 1 · 2018-05-20T21:23:48

#3x + 2y= 7#

the easiest way to do this is start with point slope form:

#y – y_1 = m(x – x_1)#

m = your slope
#(x_1, y_1) =# your point

#y – (-5) = -3/2(x – 1)#

#y +5= -3/2(x – 1)#

Now we need to do a little algebra to get the equation in standard form:

#Ax+By=C#, where A, B and C are relatively prime integers.

#y +5= -3/2x +3/2#

#3/2x + y= 3/2 - 5#

now let's multiply through with 2 to get rid if the fractions:

#2(3/2x + y= 3/2 - 5)#

#3x + 2y= 3 - 10#

#3x + 2y= 7#