How to use the discriminant to find out what type of solutions the equation has for 2x^2 = 0?

2 Answers
Gió
May 21, 2015

Your equation is in the form ax^2+bx+c=0 where:
a=2
b=0
c=0
The discriminant is:
Delta=b^2-4ac=0-0=0
When Delta=0 you will have two real coincident solutions.
In this case x_1=x_2=0

Alan P.
May 21, 2015

The discriminant for a parabolic equation of the form
ax^2+bx+c = 0
is
Delta = b^2-4ac

Delta { (<0 rarr "no Real solutions"),(=0 rarr "1 Real solution"), (>0 rarr "2 Real solutions"):}

y=2x^2
can be re-written in the form y = ax^2+bx+c as

y = 2x^2 + (0)x + (0)

and the discriminant becomes
Delta = 0^2-4(2)(0) = 0
which implies
there is 1 Real solution.

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