What type of solutions and how many solutions does the equation $41x^2-31x-52=0$ have?

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Answer 1 · 2014-11-12T02:50:37

$41x^2-31x-52=0$

$=>{(a=41),(b=-31),(c=-52):}$

Let us compute its discriminant.

$D=b^2-4ac=(-31)^2-4(41)(-52)=9489>0$ ,

which indicates that it has two real solutions.

I hope that this was helpful.

What type of solutions and how many solutions does the equation 41x^2-31x-52=041x^2-31x-52=0 have?