How to find the y-intercept given $y = {(\frac{1}{2})}^{x} - 4$ $y= (1/2)^x - 4$ ?

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Answer 1 · 2015-05-05T21:32:51

The y-intercept is the value of $y$ $y$ at the point on the function where $x = 0$ $x=0$

$y = {(\frac{1}{2})}^{x} - 4$ $y=(1/2)^x-4$ with $x = 0$ $x=0$

$y = 1 - 4 = - 3$ $y=1 -4 = -3$

The y-intercept is at $(- 3)$ $(-3)$

Answer 2 · 2015-05-05T21:33:26

Set $x = 0$ $x=0$ in your function and remember that $a^{0} = 1$ $a^0=1$ .

How to find the y-intercept given y= (1/2)^x - 4y=(12)x−4y= (1/2)^x - 4?