How to do order of operations with brackets #2[(9-8)^2+(12-5)^2]#?

1 Answer
EZ as pi
Aug 3, 2016

#100#

Explanation:

This is all one term, but within thesquare bracket there are two terms which need to be simplified separately.

#2[color(red)((9-8))^2+ (color(blue)(12-5))^2]#

=#2[color(red)((1)^2)+ color(blue)((7)^2)]#

=#2[color(red)1+ color(blue)49]#

=#2 xx50#

=#100#

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