How do you simplify #(4-2)^3-4*8+21div3#?

Question

8701 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-20T09:40:57

#color(brown)(=> - 17#

#(4-2)^3 - 4 * 8 + 21 / 3#

#=>2^3 - 4 * 8 + 21/3, " removing parantheses"#

#=> 8 - 4*8 + 21/3, " eliminating the exponent"#

#=> 8 - 32 + 21/3, " multiplying"#

#=> 8 - 32 + 7, " dividing"#

#=> 15 - 32, " adding"#

#=> - 17, " subtracting"#