How do you simplify #(4-2)^3-4*8+21div3#? Algebra Expressions, Equations, and Functions PEMDAS 1 Answer sankarankalyanam Apr 20, 2018 #color(brown)(=> - 17# Explanation: #(4-2)^3 - 4 * 8 + 21 / 3# #=>2^3 - 4 * 8 + 21/3, " removing parantheses"# #=> 8 - 4*8 + 21/3, " eliminating the exponent"# #=> 8 - 32 + 21/3, " multiplying"# #=> 8 - 32 + 7, " dividing"# #=> 15 - 32, " adding"# #=> - 17, " subtracting"# Answer link Related questions What is PEMDAS? How do you use PEMDAS? How do you use order of operations to simplify #3(7-2)-8#? What are common mistakes students make with PEMDAS? How do you evaluate the expression #5[8+(3-1)]-2#? How do you simplify the expression #4(30-(3+1)^2)#? How do you evaluate the expression #x^4+x# if x=2? Is it okay to add first before subtracting in #4-6+3#? How do you simplify #(-3)^2+12*5#? How do you simplify #6รท2(1+2)#? See all questions in PEMDAS Impact of this question 8672 views around the world You can reuse this answer Creative Commons License