How do you simplify ${(4 - 2)}^{3} - 4 \cdot 8 + 21 \div 3$ $(4-2)^3-4*8+21div3$ ?

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Answer 1 · 2018-04-20T09:40:57

$\Rightarrow - 17$ $color(brown)(=> - 17$

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${(4 - 2)}^{3} - 4 \cdot 8 + \frac{21}{3}$ $(4-2)^3 - 4 * 8 + 21 / 3$

$\Rightarrow 2^{3} - 4 \cdot 8 + \frac{21}{3}, removing parantheses$ $=>2^3 - 4 * 8 + 21/3, " removing parantheses"$

$\Rightarrow 8 - 4 \cdot 8 + \frac{21}{3}, eliminating the exponent$ $=> 8 - 4*8 + 21/3, " eliminating the exponent"$

$\Rightarrow 8 - 32 + \frac{21}{3}, multiplying$ $=> 8 - 32 + 21/3, " multiplying"$

$\Rightarrow 8 - 32 + 7, dividing$ $=> 8 - 32 + 7, " dividing"$

$\Rightarrow 15 - 32, adding$ $=> 15 - 32, " adding"$

$\Rightarrow - 17, subtracting$ $=> - 17, " subtracting"$

How do you simplify (4−2)3−4⋅8+21÷3(4-2)^3-4*8+21div3?