How many solutions does $x^2-6=0$ have?

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Answer 1 · 2016-11-13T20:27:16

2

$x^2 - 6 = 0$

$x^2 = 6$

$x = sqrt(6)$ or $x = -sqrt(6)$

This is because $(-sqrt(6)) xx (-sqrt(6))$ is also $6$ because two negatives multiplied together make a positive.

How many solutions does x^2-6=0x^2-6=0 have?