How do you write the slope-intercept equation of a line with slope -1/2 passing through point (-3,-5)?
1 Answer
Jul 19, 2016
#y=-1/2x-13/2#
Explanation:
Given -
Slope
#x=-3#
#y=-5#
The slope and intercept form of equation is given by -
#y=mx + c#
We have
We have to find
#(-1/2)(-3)+c=-5#
#3/2+c=-5#
#c=-5-3/2=(-10-3)/2=(-13)/2#
The equation is-
#y=-1/2x-13/2#
