How do you write the hyperbola $x^2/9-4y^2/9=9$ in standard form?

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How do you write the hyperbola $x^2/9-4y^2/9=9$ in standard form?

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Answer 1 · 2016-10-20T19:18:12

The equation is $x^2/9^2-y^2/(9/2)^2=1$

Explanation:

The standard form is $x^2/a^2-y^2/b^2=1$
so we must reduce the above equation to this form
Dividing by 9, we get
$x^2/(9*9)-y^2/(81/4)=1$
Rewriting the equation
$x^2/9^2-y^2/(9/2)^2=1$
Where $a=9$ and $b=9/2$

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How do you write the hyperbola $x^2/9-4y^2/9=9$ in standard form?

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Science

Math

Humanities

... and beyond

How do you write the hyperbola x^2/9-4y^2/9=9x^2/9-4y^2/9=9 in standard form?

1 Answer

Explanation:

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Impact of this question

How do you write the hyperbola $x^2/9-4y^2/9=9$ in standard form?