How do you write the equation of the line through (4, 7) and (-2, 1) in point-slope form?

1 Answer
Ratnaker Mehta
Jul 6, 2016

y=x+3.

Explanation:

Eqn. of a line passing thro. pts. (x_1,y_1) and (x_2,y_2) is : (y-y_1)/(x-x_1)=(y_2-y_1)/(x_2-x_1).

This may not turn out to be in the Point-Slope Form [in the Usual Notation ] : y=mx+c.....................(I), but we can convert it in that form.

Instead, let us start with assuming the reqd. eqn. in the desired form, i.e., (I).

Now, (4,7) in [y=mx+c] rArr 7=4m+c........(1), & (-2,1) in [y=mx+c] rArr 1=-2m+c............(2)

(1)-(2) rArr 6=6m rArr m=1 & [m, together with (1)] rArrc=3.

finally, we have the eqn. :y=x+3.

Hope, you enjoyed it, as I do!

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