How do you write the equation of a line in slope intercept, point slope and standard form given Point: (7, -2) Slope:m = 1/2?

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Answer 1 · 2018-03-09T08:37:10

(1) Point slope form of the equation is #y + 2 = (1/2) * (x - 7)#

(2) Slope intercept form of equation #y = x/2 - 11/2#

(3) Standard form #x - 2y = 11#

#slope = m = 1/2, A(x_1, y_1) = (7, -2)#

Slope intercept form #y = mx + c#

Point slope form #(y - y_1) = m (x - x_1)#

Standard form of linear equation #Ax + By = C#

Known m, one point, equation of a line can be written using

#y - y_1 = m (x - x_1)# point slope form.

(1) Point slope form of the equation is #y + 2 = (1/2) * (x - 7)#

#2y + 4 = x - 7#

#2y = x - 7 - 4 = x - 11#

(2) Slope intercept form of equation #y = x/2 - 11/2#

(3) Standard form #x - 2y = 11#