How do you write the equation in slope intercept form of the line with x intercept of -8 and slope of -5/4?

2 Answers
Jim G.
May 30, 2017

#y=-5/4x-10#

Explanation:

#"the equation of a line in "color(blue)"slope-intercept form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))#
where m represents the slope and b, the y-intercept.

#"here "m=-5/4#

#rArry=-5/4x+blarr" partial equation"#

#"to find b, substitute " (-8,0)" into the partial equation"#

#rArr0=10+brArrb=-10#

#rArry=-5/4x-10larrcolor(red)" in slope-intercept form"#

Binayaka C.
May 30, 2017

The equation of straight line in slope intercept form is #y= -5/4x -10#

Explanation:

Given, slope # m= -5/4# , x - intercept = #-8 or (-8,0)#

Let the equation of straight line in slope intercept form is #y=mx+c# ,
Where #m and c# are slope and y-intercept.

#y = -5/4x+c# Putting #x= -8 and y=0 # in the equation , we get
#0 = -5/4*-8 +c or 0 =10+c or c= -10 #

Hence equation of straight line is #y= -5/4x -10#
graph{-5/4x-10 [-40, 40, -20, 20]} [Ans]

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