How do you write the equation in slope-intercept form of the line that has a slope of 3 and contains the point (4, 9).?

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Answer 1 · 2016-04-16T15:37:05

#y = 3x + 3#

Slope-intercept form of a line is #y = mx + c#, where #m# is the slope and #c# is the y-intercept.

The question gives us #m=3# already, so

#y = 3x + c#.

Now substitute in values for #x# and #y# from the point that has been given and rearrange to find #c#.

#9_y = 3 * 4_x + c#
#c = 9-12 = -3#

and insert this into the line equation,

#y = 3x -3#

which is your final answer.