How do you write the equation in slope intercept form given point (−1, 6) and has a slope of −3?

2 Answers
Abhishek K.
May 1, 2018

#y=-3x+3#

Explanation:

If a straight line passes through #(x_1,y_1)# and has a slope #m#, then its equation can be written as #y-y_1=m(x-x_1)#.

By utilizing the values given in question, we get the equation,

#rarry-6=-3(x-(-1))#

#rarry-6=-3x-3#

#rarry=-3x+3# which is of the form #y=mx+c# (slope intercept form.

Jim G.
May 1, 2018

#y=-3x+3#

Explanation:

#"the equation of a line in "color(blue)"slope-intercept form"# is.

#•color(white)(x)y=mx+b#

#"where m is the slope and b the y-intercept"#

#"here "m=-3#

#rArry=-3x+blarrcolor(blue)"is the partial equation"#

#"to find b substitute "(-1,6)" into the partial equation"#

#6=3+brArrb=6-3=3#

#rArry=-3x+3larrcolor(red)"in slope-intercept form"#

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