How do you write the equation below that represents the line that passes through the point (-2, -1) and has a slope of 5?

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Answer 1 · 2016-12-13T20:21:27

#y + 1 = 5(x + 2)# or #y = 5x + 9#

We can use the point-slope formula to write the equation with the information given. The point-slope formula is:

#y - y_1 = m(x - x_1)#

Where #m# is the slope and #(x_1, y_1) is the point given. Substituting the information we are given lets us write the equation as:

#y - -1 = 5(x - -2)#

#y + 1 = 5(x + 2)#

Solving for #y# let's us put this into slope-intercept form:

#y + 1 = 5x + 10#

#y + 1 - 1 = 5x + 10 - 1#

#y + 0 = 5x + 9#

#y = 5x + 9#