How do you write $log_2 32=5$ in exponential form?

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Answer 1 · 2016-07-16T21:17:16

$2^5 = 32$

$log_a b= c " is interchangeable with "a^c = b$

$log_2 32 = 5 rArr 2^5 = 32$

"The base stays the base and the other two change around."

How do you write log_2 32=5log_2 32=5 in exponential form?