How do you write #f(x) = x^2+2x-8# in vertex form?

1 Answer
Alan P.
Apr 8, 2016

vertex form: #(x-color(red)(color(white)("")(-1)))^2+color(blue)(color(white)("")(-9))# with vertex at #(color(red)(-1),color(blue)(-9))#

Explanation:

General vertex form:
#color(white)("XXX")y=color(green)(m)(x-color(red)(a))^2+color(blue)(b)# with vertex at #(color(red)(a),color(blue)(b))#

#f(x)=x^2+2x-8#

#rarr f(x)=x^2+2x+1 -9#

#rarr f(x)=(x+1)^2-9#

#rarr f(x)=color(green)(1)(x-color(red)(color(white)("")(-1)))^2+color(blue)(""(-9))color(white)("XXX")# (in complete vertex form)

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