How do you write an equation of a line with Slope = 8, passing through (4, –1)?

1 Answer
George C.
May 21, 2015

We will aim to derive the equation of the line in the standard slope-intercept form #y = mx+c#, where #m# is the slope and #c# is the intercept.

You have already been given #m=8#, so we just need to find #c#.

Subtracting #mx# from both sides of the equation #y = mx+c#, we arrive at:

#c = y - mx#.

We know that one point that satifies this equation is #(4,-1)# since the line passes through it. So we can substitute our known values #m=8#, #x=4# and #y=-1# into this formula to get #c#:

#c = y-mx = -1-(8xx4) = -1-32 = -33#

So the equation of the line is #y = 8x-33#

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