How do you write an equation of a line with Slope = –5, passing through (–4, –2)?

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Answer 1 · 2015-05-18T16:46:39

The answer is : #y = -5x -22#.

The standard form of the equation of a line is : #y=mx+c#, where #m# is the slope.

Since you have a point #(x, y) = (-4, -2)# through which your line passes, you just have to solve the following equation in order to find #c# :

#y = -5x + c#

#-2 = (-5)*(-4) + c = 20 + c#

#-22 = c#

Therefore, the equation of your line is : #y = -5x -22#.