How do you write an equation of a line with point (2,-2), slope #2/7#?

1 Answer
Jim G.
Jan 26, 2017

#y=2/7x-18/7#

Explanation:

The equation of a line in #color(blue)"point-slope form "# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))#
where m represents the slope and # (x_1,y_1)" a point on the line"#

#"here "m=2/7" and " (x_1,y_1)=(2,-2)#

substituting these values into the equation.

#y-(-2)=2/7(x-2)#

#rArry+2=2/7(x-2)larrcolor(red)" in point-slope form"#

distributing the bracket and simplifying gives an alternative version of the equation.

#y+2=2/7x-4/7#

#rArry=2/7x-18/7larrcolor(red)" in slope-intercept form"#

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