How do you write an equation of a line given point (-6, 3) and has slope 2?

1 Answer
Oct 7, 2016

#y=2x+15#

Explanation:

The equation of a line in #color(blue)"point-slope form"# is

#color(red)(bar(ul(|color(white)(a/a)color(black)(y-y_1=m(x-x_1))color(white)(a/a)|)))#
where m represents the slope and # (x_1,y_1)" a point on the line"#

here m = 2 and #(x_1,y_1)=(-6,3)#

substitute these values into the equation

#y-3=2(x-(-6))#

#rArry-3=2(x+6)rArry-3=2x+12#

#rArry=2x+15larr" in slope-intercept form"#