How do you write an equation in standard form given point (2,5) and slope 1?
2 Answers
y = x+7
Explanation:

Use the formula y=mx+c
m = gradient of graph
c= y intercept 
Substitute y,m and x in equation to find c
#5=1*2 +c#
#5=2+c#
7=c 
Replace m and c with numbers found
Therefore equation is y = x + 7
Explanation:
#"the equation of a line in "color(blue)"standard form"# is.
#color(red)(bar(ul(color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2))))#
#"where A is a positive integer and B, C are integers"#
#"begin by expressing the equation in "color(blue)"pointslope form"#
#color(red)(bar(ul(color(white)(2/2)color(black)(yy_1=m(xx_1))color(white)(2/2))))#
where m represents the slope and# (x_1,y_1)" a point on the line"#
#"here " m=1" and " (x_1,y_1)=(2,5)#
#y5=1(x(2))#
#rArry5=x+2larrcolor(red)" in pointslope form"#
#"subtract y from both sides"#
#cancel(y)cancel(y)5=x+2y#
#rArr5=x+2y#
#"subtract 2 from both sides"#
#52=xcancel(+2)cancel(2)y#
#rArr7=xy " or "#
#xy=7larrcolor(red)" in standard form"#