How do you write an equation in standard form given point (-2,4) and slope -3/2?
1 Answer
Jun 3, 2017
Explanation:
#"the equation of a line in "color(blue)"standard form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#
where A is a positive integer and B, C are integers.
#"first express the equation in "color(blue)"point-slope form"#
#color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))#
where m represents the slope and# (x_1,y_1)" a point on the line"#
#"here " m=-3/2" and " (x_1,y_1)=(-2,4)#
#rArry-4=-3/2(x+2)larrcolor(red)" in point-slope form"#
#"rearrange terms into standard form"#
#y-4=-3/2x-3#
#rArr3/2x+y=1larr" multiply through by 2"#
#rArr3x+2y=2larrcolor(red)" in standard form"#
