How do you write an equation in point slope and slope intercept form parallel to y=1/2x-1 point: (0,-4)?

1 Answer
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Oct 11, 2016

#y+4=1/2(x-0)#

Explanation:

Point slope form is #y-color(blue)(y_1)=color(magenta)m(x-color(red)(x_1))#
where #color(magenta)m=# slope and #(color(red)(x_1),color(blue)(y_1))# is a point.

Parallel lines have the same slope. The equation
#y=color(magenta)(1/2)x-1# is in the form #y=color(magenta)mx+b# where #color(magenta)m=#slope.

The slope in this example is #color(magenta)(1/2)#, and the parallel slope is also #color(magenta)(1/2)#.

The point #(color(red)(x_1),color(blue)(y_1))# is #(color(red)0,color(blue)(-4))#.

So the equation in point slope form is

#y-color(blue)(-4)=color(magenta)(1/2)(x-color(red)0)#

#y+4=1/2(x-0)#

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