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How do you write #4^(x+1) = 32# in log form?

1 Answer

Aug 25, 2016

#4^(x+1) = 32 " " hArr " "log_4 32 = x+1#

Explanation:

log form and index form are interchangeable:

#log_a b = c" " hArr" " a^c = b#

"The base stays the base and the other two swop around"

#4^(x+1) = 32 " " hArr " "log_4 32 = x+1#

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