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How do you write #3lna - 6lnb# as a single logarithm?

1 Answer

Sep 1, 2015

#3 ln(a) - 6 ln(b) = ln[(a^3)/(b^6)]#

Explanation:

#3 ln(a) - 6 ln(b) =># use law of logs : #log(m^n) = n log(m):#

#= ln(a^3) - ln(b^6) =># use: #log(m) - log(n) = log(m/n):#

#= ln[(a^3)/(b^6)]#

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