How do you use the discriminant to determine the nature of the solutions given 4x^2 + 12x = 144x2+12x=14?

1 Answer
Feb 13, 2017

368 >0368>0 and not a perfect square

Therefore, the roots will be real and unequal

Explanation:

When you are solving a quadratic equation, it is very useful to know what sort of answer you will get. This can often help in determining which method to use - for example whether to look for factors or to use the quadratic formula.

A quadratic equation is written in the form ax^2 +bx +c =0ax2+bx+c=0
Always change to this form first

The discriminant is Delta = b^2-4ac
The solutions to an equation are called the 'roots' and are referred to as alpha and beta

The value of Delta tells us about the nature of the roots.

If Delta > 0 rArr the roots are real and unequal (2 distinct roots)

If Delta > 0 " and a prefect square" rArr the roots are real, unequal andcolor(white)(.................................. .................) rational

If Delta = 0 rArr the roots are real and equal (1 root)

If Delta < 0 rArr the roots are imaginary and unequal

Note that if a " or " b are irrational, the roots will be irrational.

4x^2 +12x = 14 " "rArr" 4x^2 +12x -14 =0

Delta = b^2 -4ac

Delta = (12)^2 -4(4)(-14) = 368

368 >0 and not a perfect square

Therefore, the roots will be real and unequal