How do you use the chain rule to differentiate #y=(x^4+3x)^-2#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Monzur R. Jan 16, 2017 #dy/dx=-(8x^3+6)/(x^4+3x)# Explanation: If #y=[f(x)]^n# Then #dy/dx=n[f(x)]^(n-1)f'(x)# #y=(x^4+3x)^-2# #dy/dx=-2(x^4+3x)^-3(4x^3+3)=(-2(4x^3+3))/(x^4+3x)^3=-(8x^3+6)/(x^4+3x)^3# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1292 views around the world You can reuse this answer Creative Commons License