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How do you use the chain rule to differentiate #y=(x^2+4)^-1#?

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Apr 11, 2018

#u = x^2 +4#, therefore #y = u^-1#

#(du)/dx = 2x#

#(dy)/(du) = (-u^-2)#

#(dy)/(dx) = ((du)/(dx))((dy)/(du)) = (2x)(-u^-2) = (2x)((x^2 +4)^-2) = (2x)/(x^2 +4)^2 #

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