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How do you use the chain rule to differentiate #y=(x+1)^(-1/2)#?

1 Answer

Dec 11, 2016

The answer is #=-1/2(x+1)^(-3/2)#

Explanation:

The function is #=u^(-1/2)#

We use #(x^n)'=nx^(n-1)#

The derivative is #=(u^(-1/2))'=-1/2u^(-3/2)*u'#

Here, #y=(x+1)^(-1/2)#

#dy/dx=-1/2(x+1)^(-3/2)*1#

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