How do you use the chain rule to differentiate #y=(7-x)^4#? Calculus Basic Differentiation Rules Chain Rule 1 Answer marfre Apr 30, 2017 #y' = -4(7 - x)^3# Explanation: Use #(u^n)' = n u^(n-1) u'# Let #u = 7-x; " "u' = -1; " "n = 4# #y' = 4 (7-x)^3 (-1)# Simplify: #y' = -4 (7-x)^3# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1064 views around the world You can reuse this answer Creative Commons License