Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you use the chain rule to differentiate #y=(6-2x)^3#?

1 Answer

Mar 3, 2017

#y' = -6(6-2x)^2#

Explanation:

#y = (6-2x)^3#

Use #(u^n)' = n u^(n-1) u'#

Let #u = 6-2x#, #u' = -2; n = 3#

#y' = 3(6-2x)^2 (-2) = -6(6-2x)^2#

Related questions

See all questions in Chain Rule

Impact of this question

1142 views around the world

You can reuse this answer
Creative Commons License