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How do you use the chain rule to differentiate #y=((5x^5-3)/(-3x^3+1))^3#?

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Sahar Mulla ❤

Feb 24, 2018

#y= ((5x^2 - 3)/ (-3x^3+1))^3#

#dy/dx= 3((5x^2 - 3)/ (-3x^3+1))^2 xx (d((5x^2 - 3)/ (-3x^3+1)))/dx#

#dy/dx= 3((5x^2 - 3)/ (-3x^3+1))^2 xx [((5x^2 - 3)'(-3x^3+1)-(5x^2 - 3)(-3x^3+1)')/(-3x^3+1)^2]#

#dy/dx= 3((5x^2 - 3)/ (-3x^3+1))^2 xx [(10x(-3x^3+1)-(5x^2 - 3)(-9x^2))/(-3x^3+1)^2]#

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