How do you use the chain rule to differentiate #y=(4x+5)^5#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Narad T. Oct 20, 2016 #dy/dx=20(4x+5)^4# Explanation: Let #y=(u(x))^n# Then #dy/dx=n(u(x)^(n-1))u'(x)# Here #u(x)=4x+5# #u'(x)=4# and #y=u(x)^5# So #dy/dx=5(4x+5)^4*4=20(4x+5)^4# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 874 views around the world You can reuse this answer Creative Commons License