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How do you use the chain rule to differentiate #y=4(x^2-7x+3)^(-3/4)#?

1 Answer

Nov 1, 2016

#y'=(-3(2x-7))/(x^2-7x+3)^(7/4) = (-6x+21)/(x^2-7x+3)^(7/4) #

Explanation:

#y=4(x^2-7x+3)^(-3/4)#

#y'=-3(x^2-7x+3)^(-7/4)*(2x-7)#

#y'=(-3(2x-7))/(x^2-7x+3)^(7/4) = (-6x+21)/(x^2-7x+3)^(7/4) #

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