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How do you use the chain rule to differentiate #y=4/(sqrt(x-5)#?

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Nov 13, 2016

#y=4/(sqrt(x-5))#

We can rewrite this as:
#y=4(x-5)^(-1/2)#

Use the chain rule:
#y'=4(-1/2)(x-5)^(-3/2)(1)#

#y'=-2(x-5)^(-3/2)#

#y'=(-2)/(x-5)^(3/2)#

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