# How do you use the chain rule to differentiate y=2(x^3-x)^-2?

$- 4 {\left({x}^{3} - x\right)}^{- 3} \cdot \left(3 {x}^{2} - 1\right)$
$\frac{\mathrm{dy}}{\mathrm{dx}} = \frac{d}{\mathrm{dx}} \left(2 {\left({x}^{3} - x\right)}^{- 2}\right)$
$\frac{\mathrm{dy}}{\mathrm{dx}} = - 4 {\left({x}^{3} - x\right)}^{- 3} \cdot \frac{d}{\mathrm{dx}} \left({x}^{3} - x\right)$ (chain rule)
$\frac{\mathrm{dy}}{\mathrm{dx}} = - 4 {\left({x}^{3} - x\right)}^{- 3} \cdot \left(3 {x}^{2} - 1\right)$