How do you use the chain rule to differentiate #(ln4x)^100#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Alan N. Feb 26, 2017 #(100(ln4x)^99)/x# Explanation: #f(x) = (ln4x)^100# Applying the power rule and chain rule #f'(x) = 100* (ln4x)^99 * d/dxln4x# #= 100* (ln4x)^99 * 1/(4x) * 4# [Standard differential and chain rule] #=(100(ln4x)^99)/x# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1021 views around the world You can reuse this answer Creative Commons License