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How do you use the chain rule to differentiate #ln(-cosx)#?

1 Answer

Apr 14, 2018

#d/dxln(-cosx)=-tanx#

Explanation:

The Chain Rule, when applied to logarithms, tells us that

#d/dxln(u)=1/lnu*(du)/dx, u# is some function in terms of #x.# Here, #u=-cosx,# so we have

#d/dxln(-cosx)=1/(-cosx)*d/dx(-cosx)#

#d/dxln(-cosx)=sinx/(-cosx)#

#d/dxln(-cosx)=-tanx#

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