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How do you use the chain rule to differentiate #f(x)=(x^7-3x^2+15x^(-3/2))^6#?

1 Answer

sankarankalyanam

Oct 23, 2017

#f’(x) = 6(x^7 +-3x2 + 15 x^ -(3/2))^5 * (7x^6 -6x + 45/(2sqrtx))#

Explanation:

#f(x) = ( x^7 - 3x^2 + 15x^-(3/2))^6#

#f’(x) = 6(x^7 -3x^2 + 15 x^-(3/2))^5 * (7x^6 - 6x + ((45/2) * x^-(1/2))#

#f’(x) = 6(x^7 +-3x2 + 15 x^ -(3/2))^5 * (7x^6 -6x + 45/(2sqrtx))#

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