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How do you use the chain rule to differentiate #1/-sinx#?

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Sep 15, 2016

#f'(x) = cosx/sin^2x#

Explanation:

#f(x) = -1/sinx#

#f'(x) =-d/dx(sinx)^-1#

#= - (-1*(sinx)^-2) * d/dx sinx# (Power rule and chain rule)

#=(sinx)^-2 * cosx#

#= cosx/sin^2x#

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