How do you use the chain rule to differentiate 1/ln(4x)?
1 Answer
Mar 28, 2017
Let
Differentiating the above equation yields
Then,
= frac{d}{dv}(1/v) frac{dv}{du} frac{du}{dx}
= (-1/v^2) * (1/u) * (4)
= (-1/(ln(4x))^2) * (1/{4x}) * (4)
= -1/(x (ln(4x))^2 )